EASY LEVEL:
1.7/5 would be
a) 1.4 b)1.8 c)2 d) 1.5
2.13/16 would be
a) 0.83 b)3 c) 6 d).67
3. 16/13 would be
a)1.23 b)1.66 c) 5.67 d) 5.1
4.34/43 would be
a)0.79 b)).66 c) 4.5 d) 4.3
5. 1/10 would be
a) 0.1 b) 0.2 c) 0.4 d) 0.6
6.1/100 would be
a) 0.01 b)0.1 c) 0.001 d) 0.10
7.1/5000 would be
a) 0.005 b)0.001 c)0.002 d)0.08
8. 2/10 would be
a) 0.5 b) 0.6 c)0.3 d)0.2
9.5/100 would be
a)0.05 b)0.4 c)0.08 d) 0.10
10.4/100 would be
a)0.04 b) 0.4 c) 0.8 d) 0.56
MEDIUM LEVEL
1) 2.3 +4.9 would be
a)7.2 b) 8.9 c) 3.4 d) 1.3
2) 3.41+10.1 would be
a)13.51 b) 4.67 c) 45.12 d) 12.23
3) 34.002-12 would be
a)22.002 b) 23 c) 13 d) 24
4)(3.4)*(5.6) would be
a)19.04 b)23.61 c)41.10 d)12.23
5)(16.6)*(12.3) would be
6)0.008976 would be represented in fraction as
a) 8976/100000 b) 8976/100 c) 8976/10000 d) 8976/10000
7)(66/100)+(12/1000) would be
a)0.672 b)0.234 c)0.1234 d)0.2345
8) 18.4/2.4 would be
a)7.66 b)7.4 c) 7.3 d) 6.3
9) (891/100)-(23/1000)
a)9.133 b)6.78 c)34.6 d)34.45
10) 123.4/3.4 would be
HARD level
1.A boy was travelling at 2.6789 km/hr,find the speed would be in meter/sec.
2.Solve [{(5.566-2.45678)*3.45}/0.567]
3.Simplfy[{(7.890*3.453)/890}+5.6789]
4.If Ramesh is travelling 3.899 km/hr and took 6 hr to reach the destination.find the distance covered in meter.(speed=distance*time)
5.Suresh covers the distance 56.789 km at 6hr,the speed would be in cm/sec.
6.Suresh had 5.36kg Mangoes at Rs.560.The cost of 5gm Mangoes would be
7.Mahesh had Rs.789012.50 ,he had given 4500.25 to Suresh and Rs.678.90 to Rohan.
How many mney left with him
8.Simplyfy [{(3.5908/2.1)+(78.5*2.1)}-{89.678}]
9.Simplyfy[{(3.78/78)-6.789}*6.7]
10.Simplyfy [(567)/(90-3)*(9.657)]